
VMwareVCP-VCF Support (2V0-15.25)
Domain 10Objective 5
Given a Scenario, Troubleshoot Issues with Organizations (VM-App and All-App) Configuration VCP-VCF-SUPPORT Practice Questions (Page 2)
Part of the Troubleshooting VCF Identity Broker and VCF Automation domain, which makes up ~14% of our current practice bank.
22questions here
5free pages
7concepts
Questions 6–10
- 6
When troubleshooting synchronization issues in the All-App organization, what is a common cause?
Select an answer first - 7
A change to the VM-App organization configuration is not reflected in VCF Automation. What is a likely cause?
Select an answer first - 8
A VCF administrator is troubleshooting an issue where a group of users can see a vCenter Server resource in VCF Automation, but they cannot perform any actions on it. The administrator has verified that the group is assigned to a role in the VM-App organization. What is the most likely cause of this issue?
Select an answer first - 9
A VCF administrator has made a change to the VM-App organization configuration, adding a new identity provider mapping. After waiting for some time, the administrator notices that the change has not taken effect in VCF Automation. What is the most likely cause of this issue?
Select an answer first - 10
A VCF administrator is troubleshooting an issue where users can log in to VCF Automation, but they cannot see any services. The administrator has verified that the All-App organization is correctly mapped to the corporate Active Directory and that the users have the appropriate role. The administrator has also verified that the services are registered with the All-App organization. What is the most likely cause of this issue?
Select an answer first
Finished these 5 questions?
Review the revealed explanations, or continue through the curriculum.
Free Basic Practice is a study aid with revealable answers — not a scored exam. Examers.io is independent and not affiliated with or endorsed by VMware. “VCP-VCF-SUPPORT” is a trademark of its owner, used for identification only.